[9^(4n+2)-9^(4n+1)]/81^(2n-1)
来源:百度知道 编辑:UC知道 时间:2024/06/15 21:20:05
这道题怎么做
[9^(4n+2)-9^(4n+1)]/81^(2n-1)
=[9*9^(4n+1)-9^(4n+1)]/9^(4n-2)
=[8*9^(4n+1)]/9^(4n-2)
=[8*9^(+1)]/9^(-2)
=8*9^3
=5832
原式=9^(4n+2)-9^(4n+1)/9^(4n-2)分子上提出来9^(4n+1)得到9^(4n+1)(9-1)与分母约分得9^3(9-1)=27*8=216
9^(4n-2)[9^4-9^3]/9^(4n-2)=9^4-9^3=8*9^3=5832
[9^(4n+2)-9^(4n+1)]/81^(2n-1)
=[9^(4n+2)-9^(4n+1)]/(9^2)^(2n-1)
=[9^(4n+2)-9^(4n+1)]/9^((2n-1)*2)
=9^4-9^3
=8*9^3
=5832
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